We understand neither the worth of the initial term neither the typical distinction. Nonetheless, we can discover the worth of the typical distinction thinking about that it is a consistent worth.

After that, we deduct the worths of the terms and also divide by the distinction of their placements:

$$ d= frac {19-10} {6-3} =frac {9} {3} =3$$

Now, we can utilize the formula for the umpteenth term by thinking about the sixth term as the initial term. After that, the 10th term is currently the fifth term and also the worth of n is 5:

  • Initial term: 19
  • Common distinction: 3
  • Position of term: 5

Now, we utilize the formula with these worths:

$ latex a _ {n} =a _ {1} +( n-1) d$

$ latex a _ {4} =19+( 5-1) 3$

$ latex a _ {4} =19+( 4 )3$

$ latex a _ {4} =19 +12$

$ latex a _ {4} =31$

This term is the 10th regard to the series originally provided.



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