This instance resembles the previous one, with the distinction that we need to streamline the provided formula initially. After that, we have:
$ latex (x +7) ^ 2+( y-4) ^ 2 +6= 10$
$ latex (x +7) ^ 2+( y-4) ^ 2= 4$
Now, we contrast it with the basic type:
$ latex (x-a) ^ 2+( y-b) ^ 2= r ^ 2$
Then, we have $latex a= -7$ and also $latex b= 4$, so the facility is $latex (5, ~ -3)$.
The distance amounts to $latex r= 2$.